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EXERCISE 12.1

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QUESTION 1: The radii of two circles are 19 cm and 9 cm respectively. Find the radius of the circle which has circumference equal to the sum of the circumferences of the two circles. Answer Here r1 = 19 cm => Circumference of circle ist = 2 x π x 19 = 38 π          r2 = 9 cm   => Circumference of circle 2nd = 2 x π x 9 = 18 π Let radius of third circle = R  => Circumference of circle 3rd = 2 x π x R = 2 πR By  the question Circumference of Third circle = Circumference of circle ist + Circumference of circle 2nd => 2 πR  = 38 π + 18 π => 2 πR  = 56  π => R = 28 hence radius of third circle = 28cm. QUESTION 2: The radii of two circles are 8 cm and 6 cm respectively. Find the radius of the circle having area equal to the sum of the areas of the two circles. Answer Let the radius of the third circle be R. Area of the circle with radius R = πR 2 Area of the circle ...